x^2+7x/4=-3

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Solution for x^2+7x/4=-3 equation: 


x in (-oo:+oo)

x^2+(7*x)/4 = -3 // + 3

x^2+(7*x)/4+3 = 0

x^2+7/4*x+3 = 0

DELTA = (7/4)^2-(1*3*4)

DELTA = -143/16

DELTA < 0

x belongs to the empty set

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